Solid Al(NO3)3 is added to distilled water to produce a solution in which the concentration of nitrate, [NO3-], is 0.10 M. What is the concentration of aluminum ion, [Al3+], in this solution?
(A) 0.010 M (B) 0.033 M (C) 0.066 M (D) 0.10 M (E) 0.30M
Answer and Explanation: Looking at the formula Al(NO3)3, we notice that for 1 Al ion, there are 3 NO3 ions. Therefore when aluminum nitrate dissociates in water, it produces 1 aluminum ion and 3 nitrate ions per each formula unit.
Since we know the concentration of nitrate is 0.1, the concentration of aluminum should be 1/3 of that.
0.1 (1/3) = 0.033 M (B)
Let our amazing chemistry tutor help you in NYC and online. We love to share our passion for chemistry and problem solving with you! Click here to contact us