Draw the structural formula for at least one bromoalkene with the molecular formula C5H9Br that shows:
(a) Neither E,Z isomerism nor chirality.
(b) E,Z isomerism but not chirality.
(c) Chirality but not E,Z isomerism.
(d) Both chirality and E,Z isomerism.
In order to do this questions we must know two things. A molecule that does not have a chiral center will not be chiral. A chiral center is a carbon that is attached to four different groups. Therefore, if we need to draw a molecules with no chirality, we need to make sure there are no carbons with four different groups. In this case, we do this by putting bromine at the very end.
The second concept we need to understand is that a molecule with no E/Z will have a double bond connected to the same two groups on one side. It is easiest to just put a double bond at the end of the molecule so that it is attached to two hydrogens on one end and can not be E/Z
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