top of page

Solid Al(NO3)3 is added to distilled water to produce a solution

  • Mayya Alocci
  • Jul 6, 2017
  • 1 min read

Updated: Nov 27, 2022


Solid Al(NO3)3 is added to distilled water to produce a solution in which the concentration of nitrate, [NO3-], is 0.10 M. What is the concentration of aluminum ion, [Al3+], in this solution?

(A) 0.010 M

(B) 0.033 M

(C) 0.066 M

(D) 0.10 M

(E) 0.30M

Answer and Explanation: Looking at the formula Al(NO3)3, we notice that for one Al ion, there are three NO3 ions. Therefore when aluminum nitrate dissociates in water, it produces one aluminum ion and three nitrate ions per each formula unit.

Since we know the concentration of nitrate is 0.1, the concentration of aluminum should be 1/3 of that.

0.1 (1/3) = 0.033 M (B)

Let our amazing chemistry tutor help you in Washington, DC and online. We love to share our passion for chemistry and problem solving with you! Click here to contact us


 
 
 

2 Comments

Rated 0 out of 5 stars.
No ratings yet

Add a rating
Guest
Oct 30, 2024
Rated 5 out of 5 stars.

Thank you for your explanation, and for teaching me how to represent the solutions.

Like
Mayya Alocci
Nov 09, 2024
Replying to

You are welcome! I am glad you found it helpful.

Like

Ready For Chemistry Tutoring?

I tutor all levels of chemistry including general and organic chemistry.

Click To Learn More

What subject are you taking?
Regents Chemistry
General Chemistry
Organic Chemistry

Join our email list 

COPYRIGHT © 2025 - ALL RIGHTS RESERVED. 

bottom of page