Identify the Lewis acid and Lewis base in the following reactions.(CH₃)₃N(g) + BF₃(g) ⇌ (CH₃)₃NBF₃(s) and F-(aq) + BF₃(aq) ⇌ BF₄-(aq)
- Mar 22
- 1 min read
Identify the Lewis acid and Lewis base among the reactants in each equation.
(CH₃)₃N(g) + BF₃(g) ⇌ (CH₃)₃NBF₃(s)
F-(aq) + BF₃(aq) ⇌ BF₄-(aq)
Solution:
Lewis base is an electron pair donor and Lewis acid is an electron pair acceptor. Lewis base will have a lone pair of electrons while Lewis acid will have an incomplete octet so it could accept a pair of electrons. (CH₃)₃N(g) + BF₃(g) ⇌ (CH₃)₃NBF₃(s)
(CH₃)₃N is a Lewis base because nitrogen has a pair of electrons it can donate. BF₃ is a Lewis acid because boron has an incomplete octet and can accept a pair of electrons.
F−(aq) + BF3(aq)⇌ BF4−(aq) F- is a Lewis base because fluoride ion has a pair of electrons it can donate.
BF₃ is a Lewis acid because boron has an incomplete octet and can accept a pair of electrons.
PS: If you see a negative charge that means you have a base and a positive charge will mean acid.
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