Calculate the solubility of the following compound in moles per liter: PbI2, Ksp = 1.4 x 10-8.A) 1.

Calculate the solubility of the following compound in moles per liter: PbI2, Ksp = 1.4 x 10^-8.
 A) 1.4 x 10^-8 M

B) 0.0019 M

C) 5.6 x 10^-8 M

D) 0.0024 M

E) 0.0015 M

Solution:

PbI2(s) <--> Pb^2+(aq) + 2I- (aq)

I 0 0

C X 2X

E X 2X

Ksp = 1.4 x 10^-8 = [Pb^2+][I-]^2

Ksp = 1.4 x 10^-8 = x(2x)^2 = 4x^3

X= 0.0015 M

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