NY Regents Chemistry Exam June 2022
40 Solid aluminum has a specific heat capacity of 0.90 J/g•K. How many joules of heat are absorbed to raise the temperature of 24.0 grams of aluminum from 300. K to 350. K?
(1) 22 J
(2) 45 J
(3) 1100 J
(4) 1200 J
Explanation: If we take a look at Table T on the Reference Table, we can find the formula for heat that has a temperature change. The formula is q=mCΔT where q is heat, m is mass, c is specific heat capacity and ΔT is final - initial temperature. q = (24.0 grams)(0.90 J/g•K.)(350K-300K) = 1080J
Answer: 3