The weight of H2SO4 (molecular weight 98.1) in 50.0 milliliters of a 6.00-molar solution is
(A) 3.10 grams
(B) 12.0 grams
(C) 29.4 grams
(D) 294 grams
(E) 300. grams
Molarity= moles of solute/Liters of solution
We plug in molarity and volume (convert ml to L by dividing by 1000), to get 6M = moles/ 0.05L
moles = 0.3 moles of H2SO4
Now, we have to cover moles to grams
0.3 moles of H2SO4 ( 98.1 grams/mole) = 29.43 grams.
The correct answer is C
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