Preparation for AP Chemistry exam.
AP chemistry exam is 3 hours and 15 minutes long. It includes a 90-minute multiple-choice section that has 60 questions and a 105-minute free-response section that consists of 7 questions. A calculator is not permitted on the first section but is permitted on the free response section. The test also provides students with a periodic table as well as equations and constants sheet.
AP chemistry is scored on a scale from 1 to 5. Generally, students who get 4 or 5 on the test, can get credit for the class at their college.
AP Chemistry consists of the following topics: Structure of the atom, periodic table, ionic and covalent compounds, stoichiometry, gases, liquids and solids, solutions, chemical equilibrium, kinetics, thermodynamics, electrochemistry, acids and bases, laboratory.
College Board provides free response questions from the official AP chemistry tests on their website.
At Transformation Tutoring to prepare for the AP chemistry test, we suggest first to review all the necessary chapters. A Princeton Review AP chemistry book or any other review book would be sufficient, along with the textbook the student used throughout the year. The key to doing well on the AP Chemistry test is a lot of practice! Taking timed exams and going over questions the student was not sure or got wrong is crucial. Practice can come from the official resources released by the college board along with tests and questions releases by the tutoring companies such as Princeton Review and Kaplan. Since the test is 50% multiple choice and 50% free response questions, students should divide their time equally preparing for both sections.
Let's now take an example of AP chemistry multiple choice test question.
Solid Al(NO3)3 is added to distilled water to produce a solution in which the concentration of nitrate, [NO3-], is 0.10 M. What is the concentration of aluminum ion, [Al3+], in this solution?
(A) 0.010 M (B) 0.033 M (C) 0.066 M (D) 0.10 M (E) 0.30M
Solution: Looking at the formula of aluminum nitrate we see that one mole of AL(NO3)3 will dissociate, since its an ionic compound, into 1 mole of aluminum ion and 3 moles of nitrate ions. Therefore, there should be three times as many nitrate ions as aluminum. Since the concentration of nitrate is .1M, the concentration of Aluminum ions should be .1M/3 = 0.033M giving us choice B as the correct answer choice.
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