If g(x)= -4x^2-3x+2, determine g(-2)?
If g(x)= -4x^2-3x+2, determine g(-2)?
Algebra 1, August 2019 Regent exam
Answer and Explanation:
We have a function g of x, where x can be any number or variable. To calculate g(-2), all we need to do is to plug in -2 in the equation everywhere we see x.
Therefore, this equation becomes g(-2)= -4(-2)^2-3(-2)+2 = -4(4)+6+2= -8
The answer for this problem is -8
Hint: Every time we have a function such as g(x) and are asked to calculate g of something, we just plug that something instead of x.
Let's take a look at a couple of other examples.
Lets say we have f(x) = 3x-5
Let's now calculate f(3), f(2a) and f(3b-4)
Again, we need to keep in mind wherever we see x, just plug in the new value we see in parenthesis for the function.
f(3) = 3(3)-5 = 4
f(2a) = 3(2a)-5 = 6a-5
f(3b-4) = 3(3b-4) -5 = 9b-12-5= 9b-17
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