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# How To Balance Chemical Equations? (Step By Step Guide)

A balanced chemical equation has the same number of atoms of each element on the left (reactant) and right (product) sides.

We balance a chemical equation by adding coefficients in front of molecules.

Example1

Let's do this step by step with an example.

N2 + H2 NH3

1. Write out the elements present on both sides of the equation.

N2 + H2 NH3

N N H

2. Put the number of atoms of each element on both sides. If there is no subscript next to an element, that means there is 1 atom of that element.

N2 + H2 NH3

 N=2 N=1 H=2 H=3

3. Put the coefficients in front of compounds so that the numbers of each element are equal on both side of the equation. The coefficient in front of a compounds gets distributed to all the elements in that compound. For example, 3H2O means 3*2 = 6 atoms of hydrogen and 3 atoms of oxygen.

N2 + H2  2NH3

 N=2 N=2 H=2 H=6

Now, the number of nitrogen atoms is equal but not hydrogen atoms.

N2 + 3H2  2NH3

N=2 N=2

H=6 H=6

The numbers of atoms of each element are equal on both sides of the equation. Equation is balanced!

Example 2

Na3PO4 + KOH   NaOH + K3PO4

1. Write out the elements present on both sides of the equation. If we see the same polyatomic ion on both sides of the equation, we can put it instead of separating it into elements.

Na3PO4 + KOH   NaOH + K3PO4

 Na Na PO4 PO4 K K OH OH

2. Put the number of atoms of each element on both sides.

Na3PO4 + KOH NaOH + K3PO4

 Na =3 Na =1 PO4=1 PO4=1 K=1 K=3 OH=1 OH=1

3. Put the coefficients in front of compounds so that the numbers of each element are equal on both side of the equation.

We first, add 3 in front of NaOH to make the number of Na atoms equal. Then, we put a 3 in front of KOH to make the number of K atoms equal.

Na3PO4 + 3KOH 3NaOH + K3PO4

 Na =3 Na =3 PO4=1 PO4=1 K=3 K=3 OH=3 OH=3

Example 3

C3H6 + O2 CO2 + H2O

1. Write out the elements present on both sides of the equation.

C3H6 + O2 CO2 + H2O

 C C H H O O

2. Put the number of atoms of each element on both sides.

C3H6 + O2 CO2 + H2O

 C=3 C=1 H=6 H=2 O=2 O=3

3. Put the coefficients in front of compounds so that the numbers of each element are equal on both side of the equation.

First we balance the carbons.

C3H6 + O2 3CO2 + H2O

 C=3 C=3 H=6 H=2 O=2 O=7

Next, we balance the hydrogens.

C3H6 + O2 3CO2 + 3H2O

 C=3 C=3 H=6 H=6 O=2 O=9

Last, we need to balance the oxygens. There is no whole number that we can multiply by to get 9. Therefore, we will use a fraction: 9/2

C3H6 + 9/2O2 3CO2 + 3H2O

 C=3 C=3 H=6 H=6 O=9 O=9

Finally, we need to get rid of the fraction by multiplying the whole equation by 2.

2(C3H6 + 9/2O2 3CO2 + 3H2O)

2C3H6 + 9O2 6CO2 + 6H2O

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