In the n=3 principal level, what is the maximum number of electrons that could have l=2?
- Feb 8
- 1 min read
In the n=3 principal level, what is the maximum number of electrons that could have l=2?
Solution:
Let's go over the quantum numbers.
n = Energy Level
n can be be any positive integer: 1,2,3,4,5,6....
l = Angular Momentum Quantum Number (Orbital shape)
l can go from 0 to n-1
Example: If n=2→ l: 0,1. If n=4→ l= 0,1,2,3.
ml = Magnetic Quantum Number ( Orbital Orientation)
ml can go from -l....0....+l
Example if l=3 → ml = -3,-2,-1,0,1,2,3
If l=2, then ml = -2,-1,0,1,2. Each ml value can hold a maximum of two electrons (with opposite spins), giving a total of 5×2=10electrons.
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