In which of the following processes will ∆S° be negative?
- Mayya Alocci
- Apr 14
- 1 min read
In which of the following processes will ∆S° be negative?
(A) C2H5OH(l) -> C2H5OH(g)
(B) NaCl(s) -> NaCl(l)
(C) CO2(s) -> CO2(g)
(D) Cl2(g) -> Cl2(l)
Solution: ∆S° is the change in entropy. You can think of entropy as disorder. When disorder is increased, change in entropy will be positive. When disorder is decreased, change in entropy is negative. Gases are more disordered than liquids which are more disordered than solids. Therefore, going from gas (g) to liquid(l) would result in a decrease of disorder, making choice D the correct answer choice.
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