August 2018 NY Regents Chemistry Exam
39 The least polar bond is found in a molecule of
(1) HI (2) HF
(3) HCl
(4) HBr
Solution: The polarity of the bond is based on the electronegativity difference. Electronegativity values can be found in Table S on the Reference Table. All we need to do is to find electronegativity value for each element holding a bond. Then, subtract the bigger number from the smaller number to find electronegativity difference. The pair that has the smallest electronegativity difference represents the least polar bond.
Answer:1
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