The valve between a 3.25-L tank containing O2(g) at 7.36 atm and a 3.30 L tank containing Ne(g) at 6.00 atm is opened. Calculate the ratio of partial pressures (O2:Ne) in the container. a. 0.93
b. 1.14
c. 1.21
d. 0.878
e. 0.551
Explanation:
Initial conditions: O2
V=3.25-L
P = 7.36 atm
Initial conditions: Ne
V= 3.30 L
P=6.00 atm
Final conditions:
Since the valve is opened, the new volume would be 3.25L + 3.30L = 6.55L
We can use P1V1=P2V2 for each gas to calculate the new pressure of each gas.
O2: 7.36 atm(3.25L) = P2(6.55L)
P2= 3.65 atm
Ne: 6.00 atm(3.30 L)=P2(6.55L)
P2 = 3.02 atm
Let's now do the ratio of O2 to Ne pressure. 3.65 atm/3.02 atm = 1.21
Answer: c