What is the Lewis Dot Structure of N2H4

What is the Lewis Dot Structure of N2H4

Solution:

Steps for Drawing Lewis Dot Structure:

1. Calculate the total number of valence electrons in a molecule (group number = number of valence electrons)

2. Draw out your molecule and put lines between atoms (bonds)

3. Subtract electrons used in bonds (2 electrons per bond) from the total number of valence electrons

4. Use the remaining electrons to make outer atoms happy (octet). Keep in mind hydrogen only wants 2 electrons.

5. If there are any electrons left, place them on the central atom.

6. Check if everyone is happy(octet). If not use neighboring atom's lone pairs to make double and triple

   bonds.

   
   

Step 1: Total number of valence electrons for N2H4 = 5(2)+1(4) =14 electrons

Step 2:

Step 3: There are 3 bonds. Each bond is 2 electrons. We need to subtract electrons used in bonds from the total electrons. 14-(3*2) = 8 electrons left.

Step 4 and 5:

8 electrons - 8 electrons= 0 electrons left

Step 6: All the atoms are happy. The correct Lewis structure must be:

N2H2 Lewis Dot Structure

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