What is the major product in the following reaction?
![](https://static.wixstatic.com/media/d261a6_734bb31fb3f24541bbc89983421cc1eb~mv2.png/v1/fill/w_82,h_97,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/d261a6_734bb31fb3f24541bbc89983421cc1eb~mv2.png)
Solution:
We have a tertiary substrate (bromine is attached to carbon which is attached to three other carbons) and a strong base, OH-. Please note KOH consists of K+ and OH-. OH- is a strong base. Therefore, E2 would be the major reaction, resulting in a double bond. We always want to make the most substituted double bond, making choice D the correct answer.
![](https://static.wixstatic.com/media/d261a6_4e52c8908dec412dae3b8af52f88a509~mv2.png/v1/fill/w_49,h_28,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/d261a6_4e52c8908dec412dae3b8af52f88a509~mv2.png)