(A) 0.0188 g
(B) 0.0445 g
(C) 1.61 g
(D) 2.79 g
Solution:
Molarity = moles of solute/liters of solution
M = 0.0750M
V= 250.0ml( 1L/1000ml)= 0.250L
0.0750M = moles of solute/0.250L
moles of solute = 0.0188molMg(NO3)2
Now, lets convert moles to grams using the molar mass from the Periodic Table.
0.0188molMg(NO3)2 ( 148.33g/1mol) = 2.79g Mg(NO3)2
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