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What mass of potassium sulfate, K2SO4, is needed to prepare 500. mL of a 0.200 M K2SO4 aqueous solut


What mass of potassium sulfate, K2SO4, is needed to prepare 500. mL of a 0.200 M K2SO4 aqueous solution?


Solution:

Molarity = moles of solute/ Liters of solution

We have molarity and volume. We can find moles of solute.

500ml (1L/1000ml) = .500L


0.200 = x/.5L

x = .1 moles


Now, we can convert moles to grams.

K2SO4 molar mass is 174.259 g/mol (from the Periodic Table)


0.1moles ( 174.259g/1mol) = 17.4grams

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